Chapter 14

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All the offspring of a cross between a red-flowered plant and a white-flowered plant have pink flowers. This means that the allele for red flowers is ________ to the allele for white flowers.

A) dominant

B) codominant

C) pleiotropic

D) incompletely dominant

E) recessive

D) incompletely dominant

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Related Quiz Content
  • yosay
    Answered in Chapter 14
    In some plants, a true-breeding, red-flowered strain gives all pink flowers when crossed with a white-flowered strain: RR (red) × rr (white) →Rr (pink). If flower position (axial or terminal) is inherited as it is in peas (see Table 14.1 in your text), what will be the ratios of genotypes and phenotypes of the F1 generation resulting from the following cross: axial-red (true-breeding) × terminal-white? What will be the ratios in the F2 generation?

    Parental cross is AARR × aarr. Genotype of F1 is AaRr, phenotype is all axial-pink. Genotypes of F2 are 4 AaRr : 2 AaRR : 2 AARr : 2 aaRr : 2 Aarr : 1AARR : 1 aaRR : 1 AArr : 1 aarr. Phenotypes of F2 are 6 axial-pink : 3 axial-red: 3 axial-white : 2 terminal-pink : 1 terminal-white : 1 terminal red.

  • yosay
    Answered in Chapter 14
    A black guinea pig crossed with an albino guinea pig produces 12 black offspring. When the albino is crossed with a second black one, 7 blacks and 5 albinos are obtained. What is the best explanation for this genetic situation? Write genotypes for the parents, gametes, and offspring
    Albino (b) is a recessive trait; black (B) is dominant. First cross: parents BB × bb; gametes B and b; offspring all Bb (black coat). Second cross: parents bb × Bb; gametes 1/2 B and 1/2 b (heterozygous parent) and b; offspring 1/2 Bb and 1/2 bb
  • yosay
    Answered in Chapter 14

    In sesame plants, the one-pod condition (P) is dominant to the three-pod condition (p), and normal leaf (L) is dominant to wrinkled leaf (l). Pod type and leaf type are inherited independently. Determine the genotypes for the two parents for all possible matings producing the following offspring:

    A) 318 one-pod, normal leaf : 98 one-pod, wrinkled leaf

    B) 323 three-pod, normal leaf : 106 three-pod, wrinkled leaf

    C) 401 one-pod, normal leaf

    D) 150 one-pod, normal leaf : 147 one-pod, wrinkled leaf : 51 three-pod, normal leaf : 48 three-pod, wrinkled leaf

    E) 223 one-pod, normal leaf : 72 one-pod, wrinkled leaf : 76 three-pod, normal leaf; 27 three-pod, wrinkled leaf

    A)PPLl × PPLl, PpLl, or ppLl

    B)ppLl × ppLl

    C)PPLL × any of the 9 possible genotypes or PPll × ppLL

    D)PpLl × Ppll

    E) PpLl × PpLl

  • yosay
    Answered in Chapter 14

    A man with type A blood marries a woman with type B blood. Their child has type O blood. What are the genotypes of these individuals? What other genotypes, and in what frequencies, would you expect in offspring from this marriage?

    Man IAi; woman IBi; child ii. Other genotypes for children are 1/4 IAIB ,1/4 IAi, 1/4 IBi

  • yosay
    Answered in Chapter 14

    Phenylketonuria (PKU) is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers, have three children, what is the probability of each of the following?

    A) All three children are of normal phenotype.

    B) One or more of the three children have the disease.

    C) All three children have the disease.

    D)At least one child is phenotypically normal.

    A) 3/4 × 3/4 × 3/4 = 27/64

    B) 1 - 27/64 = 37/64

    C) 1/4 × 1/4 × 1/4 = 1/64

    D) 1 - 1/64 = 63/64

  • yosay
    Answered in Chapter 14

    The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes?

    A) aabbccdd

    B) AaBbCcDd


    D) AaBBccDd

    E) AaBBCCdd

    A) 1/256

    B) 1/16

    C) 1/256

    D) 1/64

    E) 1/128

  • yosay
    Answered in Chapter 14

    What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent assortment of all gene pairs.)

    A) AABBCC × aabbcc → AaBbCc

    B) AABbCc × AaBbCc → AAbbCC

    C) AaBbCc × AaBbCc → AaBbCc

    D) aaBbCC × AABbcc → AaBbCc

    A) 1

    B) 1/32

    C) 1/8

    D) 1/2

  • yosay
    Answered in Chapter 14

    Karen and Steve each have a sibling with sickle-cell disease. Neither Karen nor Steve nor any of their parents have the disease, and none of them have been tested to reveal sickle-cell trait. Based on this incomplete information, calculate the probability that if this couple has a child, the child will have sickle-cell disease.

  • yosay
    Answered in Chapter 14

    In 1981, a stray black cat with unusual rounded, curled-back ears was adopted by a family in California. Hundreds of descendants of the cat have since been born, and cat fanciers hope to develop the curl cat into a show breed. Suppose you owned the first curl cat and wanted to develop a true-breeding variety. How would you determine whether the curl allele is dominant or recessive? How would you obtain true-breeding curl cats? How could you be sure they are true-breeding?

    Matings of the original mutant cat with true-breeding noncurl cats will produce both curl and noncurl F1 offspring if the curl allele is dominant, but only noncurl offspring if the curl allele is recessive. You would obtain some true-breeding offspring homozygous for the curl allele from matings between the F1 cats resulting from the original curl × noncurl crosses whether the curl trait is dominant or recessive. You know that cats are true-breeding when curl × curl matings produce only curl offspring. As it turns out, the allele that causes curled ears is dominant
Chapter 14
Chapter 14
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